LANGUAGE CALCULATOR
Students are beloved dear students here teacher teach mathematical knowledge involves (), x, divide, +, and - BASED 'HAFIZUL METHODS. This question is usually popular among students who would sit on the PMR examination.
Students are beloved teacher of students worldwide and gentlemen, this method created as a result of teacher experience gained from the teacher training college teacher Sultan Abdul Halim AND OPEN UNIVERSITY MALAYSIA.
Once you know, understand and master this method, students can solve the question of the question without using the 'calculator' again.
When the existence of problems involving (), x, divide, +, and -. The first thing students should do is to complete this operation within the () first does not matter whether () is at the front, middle or back.
The second thing to do is solve problems involving x or division in which is mentioned first. If the first division finish first division and if x x. finish
The third thing the students need to do is solve problems involving + or - which was mentioned earlier. If the + + and should finish first - first solve -.
After completing all of them, then try Check the calculator. Right? Good luck and successful students sitting.
Let's look at the examples that have been teachers produce:
1. 7 x 6 + (12-3) - 4 ÷ 2 =?
= 42 + 9-4 ÷ 2
= 51-2
= 49.
2. 12 + 3 - (6 ÷ 2) x 6 ÷ 2 =?
= 15 - 3 x 6 ÷ 2
= 15-9 = 6.
3. 14-6 + 7 x 4 ÷ (12-8) =?
= 8 + 7 x 4 ÷ 4
= 8 + 7 = 15.
4. 18 + 12-6 x 4 ÷ 2 + (6 x 3) =?
= 18 + 12-12 + 18
= 36.
5. (12 + 6) ÷ 2 x 6 + 7-3 =?
= 18 ÷ 2 x 6 + 7-3
= 54 + 7-3
= 58.
6. 12 + 6 ÷ 2 x (6 + 7) - 3 =?
= 12 + 6 ÷ 2 x 13-3
= 12 + 39-3
= 51-3 = 48.
7. 6 x 6 + (4 ÷ 2) - 6 ÷ 2 =?
= 36 + 2-6 ÷ 2
= 36 + 2-3
= 35.
8. 8 x 4 + 7 - (6 x 2) ÷ 4 =?
= 32 + 7-12 ÷ 4
= 32 + 7-3
= 36.
9. 8 x (4 + 7) - 6 x 2 ÷ 4 =?
= 8 x 11-6 x 2 ÷ 4
= 88-3
= 85.
10. 7 + 4 x (6 ÷ 2) - 3 + (7 2) =?
= 7 + 4 x 3-3 + 9
= 7 + 12-3 + 9
= 19-3 + 9
= 16 + 9
= 25.
No hp teacher: 0129676083 and No. tel: 097257521
Students are beloved teacher of students worldwide and gentlemen, this method created as a result of teacher experience gained from the teacher training college teacher Sultan Abdul Halim AND OPEN UNIVERSITY MALAYSIA.
Once you know, understand and master this method, students can solve the question of the question without using the 'calculator' again.
When the existence of problems involving (), x, divide, +, and -. The first thing students should do is to complete this operation within the () first does not matter whether () is at the front, middle or back.
The second thing to do is solve problems involving x or division in which is mentioned first. If the first division finish first division and if x x. finish
The third thing the students need to do is solve problems involving + or - which was mentioned earlier. If the + + and should finish first - first solve -.
After completing all of them, then try Check the calculator. Right? Good luck and successful students sitting.
Let's look at the examples that have been teachers produce:
1. 7 x 6 + (12-3) - 4 ÷ 2 =?
= 42 + 9-4 ÷ 2
= 51-2
= 49.
2. 12 + 3 - (6 ÷ 2) x 6 ÷ 2 =?
= 15 - 3 x 6 ÷ 2
= 15-9 = 6.
3. 14-6 + 7 x 4 ÷ (12-8) =?
= 8 + 7 x 4 ÷ 4
= 8 + 7 = 15.
4. 18 + 12-6 x 4 ÷ 2 + (6 x 3) =?
= 18 + 12-12 + 18
= 36.
5. (12 + 6) ÷ 2 x 6 + 7-3 =?
= 18 ÷ 2 x 6 + 7-3
= 54 + 7-3
= 58.
6. 12 + 6 ÷ 2 x (6 + 7) - 3 =?
= 12 + 6 ÷ 2 x 13-3
= 12 + 39-3
= 51-3 = 48.
7. 6 x 6 + (4 ÷ 2) - 6 ÷ 2 =?
= 36 + 2-6 ÷ 2
= 36 + 2-3
= 35.
8. 8 x 4 + 7 - (6 x 2) ÷ 4 =?
= 32 + 7-12 ÷ 4
= 32 + 7-3
= 36.
9. 8 x (4 + 7) - 6 x 2 ÷ 4 =?
= 8 x 11-6 x 2 ÷ 4
= 88-3
= 85.
10. 7 + 4 x (6 ÷ 2) - 3 + (7 2) =?
= 7 + 4 x 3-3 + 9
= 7 + 12-3 + 9
= 19-3 + 9
= 16 + 9
= 25.
No hp teacher: 0129676083 and No. tel: 097257521
Ulasan
Catat Ulasan